(2x^2+3x)^2-7(2x^2+3x)=-10

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Solution for (2x^2+3x)^2-7(2x^2+3x)=-10 equation: 



(2x^2+3x)^2-7(2x^2+3x)=-10

We move all terms to the left:

(2x^2+3x)^2-7(2x^2+3x)-(-10)=0

We add all the numbers together, and all the variables

(2x^2+3x)^2-7(2x^2+3x)+10=0

We multiply parentheses

-14x^2+(2x^2+3x)^2-21x+10=0

We add all the numbers together, and all the variables

-14x^2-21x+(2x^2+3x)^2+10=0

We move all terms containing x to the left, all other terms to the right

-14x^2-21x+(2x^2+3x)^2=-10

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